Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution R.D.Sharma Class 12 Chapter 30 Probability Exercise 30.4 Question 22 Sub Question 1 Maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 30 Probability  Exercise 30.4 Question 22 Sub Question 1 Maths Textbook Solution.

Answers (1)

Answer: \frac{16}{121}

Hint:  Probability=\frac{No\: of\: outcomes}{Total\: outcomes}

Given: An urn contains 4 red and 7 black balls. Two balls are drawn at random with replacement. Find the probability of getting 1) 2 red balls

Solution:           

                    Total\: balls = 4 red+7 black=11 balls

                    \begin{aligned} \mathrm{P}(2 \text { red balls }) &=\mathrm{P}(\text { first ball is red }) \times \mathrm{P}(\text { second ball is red }) \\ &\left.=\frac{4}{11} \times \frac{4}{11} \ldots \text { as replacement is allowed }\right\} \\ &=\frac{16}{121} \end{aligned}

                       
                                         

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE board exams 2025 from February 15; Class 10, 12 subject-wise marks distribution
anam-khan

CBSE Date Sheet 2025: Class 10, 12 board exam dates soon on cbse.gov.in; previous trends, sample papers
anam-khan

CBSE Board Exams 2025: 75% attendance must for students to be eligible, reiterates board

Latest Question