Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 chapter 12 Derivative as a Rate Measurer exercise multiple choise question 8 maths

Explain solution RD Sharma class 12 chapter 12 Derivative as a Rate Measurer exercise multiple choise question 8 maths

Answers (1)

Answer:

(d)\; \; 3,\; \; \frac{1}{3}

Hint:

Here, we use the basic concept of algebra.

Given:

x^{3}-5x^{2}+5x+8

Solution:

p(x)=x^{3}-5x^{2}+5x+8 \quad\quad\quad\quad......(i)

→ Differentiating (i) with respect to t,we get

\begin{aligned} &\frac{d p(x)}{d t}=\left(x^{3}-5 x^{2}+5 x+8\right) \frac{d x}{d t}=2 \frac{d x}{d t}\\ &2 \frac{d x}{d t}=\left(3 x^{2}-10 x+5\right) \frac{d x}{d t}\\ &=3 x^{2}-10 x+5=2\\ &=3 x^{2}-10 x+3=0\\ &\rightarrow \text { Factorizing the above quadratic equation, }\\ &\text { we get }(3 x-1)(x-3)=0\\ &\Rightarrow x=\frac{1}{3} \text { and } x=3 \end{aligned}

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2025 Live: UP Board exams from February 24; CBSE, BSEB date sheet soon
anam-khan

CBSE Date Sheet 2025 Live: Class 10, 12 board exam dates soon; syllabus, sample papers
anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea

Latest Question