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Explain solution RD Sharma class 12 Chapter 17 Maxmima and Minima Exercise Case Study Questions question 4 subquestion (iii)

Answers (1)

Answer:   10 \mathrm{x}-\left(\frac{\pi+4}{2}\right) \mathrm{x}^{2}

Hint: use the  basic concept.

Solution:

\begin{aligned} \text { Area } &=(2 x)(2 y)+\frac{\pi x^{2}}{2} \\ & \end{aligned}

            =4 x\left(\frac{10-\pi x-2 x}{4}\right)+\frac{\pi x^{2}}{2}

\begin{aligned} A &=10 x-2 x^{2}-\frac{\pi x^{\wedge} 2}{2} \\ \end{aligned}

=10 x-\frac{4 x^{2}+\pi x^{2}}{2} \\

A =10 x-x^{2}\left(\frac{\pi+4}{2}\right)

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