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Explain solution RD Sharma class 12 Chapter 17 Maxmima and Minima Exercise Case Study Questions question 7 subquestion (v)

Answers (1)

Answer:  40(4 \sqrt{3}+3)

Hint: use basic concept.

Solution:

\begin{aligned} &\mathrm{GA}+\mathrm{GB}+\mathrm{GC}=? \\ \end{aligned}

\mathrm{~GB}=\mathrm{GA}=\mathrm{x} \\

\Rightarrow \frac{2}{\mathrm{x}}=\frac{1}{\sqrt{\mathrm{x}^{2}-160^{2}}}

\begin{aligned} &\mathrm{x}=2 \mathrm{x}-160 \\ \\ \end{aligned}

\mathrm{x}=320 / \mathrm{v} 3

\begin{array}{ll} \mathrm{GA}+\mathrm{GB}+\mathrm{GC} =120+160 \sqrt{3} \\ \end{array}

                                 =40(4 \sqrt{3}+3)

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