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  • Explain solution RD Sharma class 12 chapter 28 The Plane exercise very short answer type question 8 maths

Explain solution RD Sharma class 12 chapter 28 The Plane exercise very short answer type question 8 maths

Answers (1)

Answer:

 \sqrt{14}\: \: units

Hint:

 Distance =

\frac{\left | D_1-D_2 \right |}{\sqrt{a^2+b^2+c^2}}

Given:

 parallel planes are 2x - y + 3z = 4 and 2x - y + 3z = 18

Solution:

2x - y + 3z = 4

2x - y + 3z = 18

Distance =

\frac{\left | D_1-D_2 \right |}{\sqrt{a^2+b^2+c^2}}

\sqrt{a^2+b^2+c^2}=\sqrt{(2)^2+(-1)^2+(3)^2}=\sqrt{4+1+9}=\sqrt{14}\: units

D_1-D_2=18-4=14

\therefore \text { Distance }=\frac{14}{\sqrt{14}}=\sqrt{14}\: units

Posted by

Gurleen Kaur

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