Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • explain solution RD Sharma class 12 chapter Differentiation exercise 10.2 question 8 maths

explain solution RD Sharma class 12 chapter Differentiation exercise 10.2 question 8 maths

Answers (1)

Answer: \frac{2}{(2 x-3) \log 7}

Hint:  You must know the rules of solving derivative of logarithm function.

Given: \log _{7}(2 x-3)

Solution:

Let   y=\log _{7}(2 x-3)

Differentiating with respect to x,

\frac{d y}{d x}=\frac{d}{d x}\left[\log _{7}(2 x-3)\right]

\frac{d y}{d x}=\frac{d}{d x}\left[\frac{\log (2 x-3)}{\log 7}\right]                        \left[\therefore \log _{a} b=\frac{\log b}{\log a}\right]

\begin{aligned} &\frac{d y}{d x}=\frac{1}{\log 7} \frac{d}{d x}[\log (2 x-3)] \\ &\frac{d y}{d x}=\frac{1}{\log 7} \times \frac{1}{(2 x-3)} \frac{d}{d x}(2 x-3) \end{aligned}          [   using chain rule ] 

\frac{d y}{d x}=\frac{2}{(2 x-3) \log 7}

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2025 Live: UP Board exams from February 24; CBSE, BSEB date sheet soon
anam-khan

CBSE Date Sheet 2025 Live: Class 10, 12 board exam dates soon; syllabus, sample papers
anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea

Latest Question