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  • Explain solution RD Sharma class 12 chapter Probability exercise 30.2 question 14 maths

Explain solution RD Sharma class 12 chapter Probability exercise 30.2 question 14 maths

Answers (1)

Answer:

 \begin{aligned} &\frac{1}{24} \end{aligned}

Hint:

\begin{aligned} &\text { Probability }=\frac{\text { No. of event favourable outcomes }}{ \text { Total no. of outcomes }} \end{aligned}

Given,

            A=A white ball in the 1st draw

            B=A black ball in the 2nd draw

            C=A red ball in the 3rd draw

\begin{aligned} &P(A)=\frac{4}{16}=\frac{1}{4}\\ &P\left ( \frac{B}{A} \right )=\frac{7}{15}\\ &P\left ( \frac{C}{B\cap A} \right )=\frac{5}{14}\\ &\text { Required Probability }=P(A\cap B\cap C)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\times P\left ( \frac{C}{B\cap A} \right )\\ &=\frac{1}{4}\times \frac{7}{15}\times \frac{5}{14}\\ &=\frac{1}{24} \end{aligned}

Posted by

Gurleen Kaur

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