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Explain solution RD Sharma class 12 chapter Probability exercise 30.2 question 6 subquestion (iii) maths

Answers (1)

Answer:

 \frac{25}{204}

Hint:

\begin{aligned} &\text { Probability }=\frac{\text { No. of event favourable outcomes }}{ \text { Total no. of outcomes }} \end{aligned}

Given, events as follows

            Let C=A heart in the 1st throw

                   D=A red card in the 2nd throw

 Now,

\begin{aligned} &P(C)=\frac{13}{52}=\frac{1}{4}\\ &P\left ( \frac{C}{D} \right )=\frac{25}{51}\\ &\text { Required Probability }=P(C\cap D)\\ &=P(C)\times P\left ( \frac{C}{D} \right )\\ &=\frac{1}{4}\times \frac{25}{51}\\ &=\frac{25}{204} \end{aligned}

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Gurleen Kaur

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