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  • Explain solution RD Sharma class 12 chapter The Plane exercise 28.2 question 2 sub question (iii) maths

Explain solution RD Sharma class 12 chapter The Plane exercise 28.2 question 2 sub question (iii) maths

Answers (1)

Answer:

Intercepts form of the given equation is  \frac{x}{\frac{5}{2}}+\frac{y}{-5}+\frac{z}{5}=1  & its intercepts on co-ordinate axes are \frac{5}{2},-5 \; \&\; 5

Hint:

First divide the given equation by 5 then compare it with  \frac{x}{p}+\frac{y}{q}+\frac{z}{r}=1,  where p, q & r intercepts on co-ordinate axes.

Given:

Equation of plane is 2x-y+z=5 .......(i)

Explanation:

Divide equation (i) by 5

        \begin{aligned} &\frac{2 x-y+z}{5}=\frac{5}{5} \\ &\Rightarrow \frac{x}{\frac{5}{2}}-\frac{y}{5}+\frac{z}{5}=1 \end{aligned}

Compare above equation with  \frac{x}{p}+\frac{y}{q}+\frac{z}{r}=1

Here, p=\frac{5}{2}, q=-5 \; \& \; r=5

Hence, intercepts form is

        \frac{x}{\frac{5}{2}}+\frac{y}{-5}+\frac{z}{5}=1

& intercepts on co-ordinate axes are \frac{5}{2},-5\; \&\; 5

 

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