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Explain solution RD Sharma class 12 chapter The Plane exercise 28.3  question 4 sub question (i) maths

Answers (1)

Answer:

\vec{r} \cdot(2 \hat{\imath}-\hat{\jmath}+2 \hat{k})=8

Hint:

\vec{r} \cdot \vec{n}=d

Given:

2x-y+2z=8

Solution:

Vector equation of the plane is \vec{r} \cdot \vec{n}=d

\begin{aligned} &2 x-y+2 z=8 \\\\ &\Rightarrow(x \hat{\imath}+y \hat{\jmath}+z \hat{k}) \cdot(2 \hat{\imath}-\hat{\jmath}+2 \hat{k})=8 \\\\ &\vec{r} \cdot(2 \hat{\imath}-\hat{\jmath}+2 \hat{k})=8[\therefore \vec{r}=x \hat{\imath}+y \hat{\jmath}+z \hat{k}] \end{aligned}

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