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Need solution for RD Sharma Maths Class 12 Chapter 17 Maxima and Minima Excercise Case Study Based Questions question 3 subquestion (ii)

Answers (1)

Answer:   \mathrm{AR}=Rs\left(\frac{500}{\mathrm{x}}-1\right)(300+\mathrm{x})

Hint: use concept of revenue.

Solution:

Normal Revenue is

R=(500-x)(300+x)

The average revenue of the company when annual subscription is increased by Rs x per subscibers

Average revenue

                         \begin{aligned} &=\left(\frac{500-\mathrm{x}}{\mathrm{x}}\right)(300+\mathrm{x}) \\ &=\mathrm{Rs}\left(\frac{500}{\mathrm{x}}-1\right)(300+\mathrm{x}) \end{aligned}

 

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