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  • Need solution for RD Sharma maths class 12 chapter 23 Scaler and Dot Product exercise Multiple choice question 7

Need solution for RD Sharma maths class 12 chapter 23 Scaler and Dot Product exercise Multiple choice question 7

Answers (1)

Answer:  Option (a) \sqrt{3}

Hint:  Use the formula of  \vec{a} \cdot \vec{b}=|\vec{a}||\vec{b}| \cos \theta

Given:

\vec{a} \text { and } \vec{b} are unit vector

Solution:

\vec{a} \text { and } \vec{b} are unit vector

\therefore|\vec{a}|=1 \text { and }|\vec{b}|=1

We know that,

\begin{aligned} &-1<\cos \theta<1 \\\\ &-1<\vec{a} \cdot \vec{b}<1 \end{aligned} \quad[\because \cos \theta=\vec{a} \cdot \vec{b}]

So \vec{a} \cdot \vec{b}  cannot be greater than one.

Hence, option (a) is correct

Posted by

infoexpert26

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