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Need solution for RD Sharma maths class 12 chapter 28 The Plane exercise multiple choice question 11

Answers (1)

Answer:

 Option (c)

Hint:

 Use the centroid formula.

Given:

 \frac{x}{a}+\frac{y}{b}+\frac{z}{c}=k

Solution:

A plane meets the co-ordinate area of (A, B, C) such that the centroid of \Delta ABC  is the point (a,b,c).

Let the co-ordinate of the point

 A(\alpha , 0, 0),\: B(0,\beta ,0),\: C(0,0,\gamma )

By the centroid formula,

\begin{aligned} &a =\frac{\alpha +0+0}{3}\\ &\Rightarrow \alpha =3a\\ &b=\frac{0+\beta +0}{3}\\ &\Rightarrow \beta =3b\\ &c=\frac{0+0+\gamma }{3}\\ &\Rightarrow \gamma =3c \end{aligned}

The Intercept form of the plane–

\frac{x}{p}+\frac{y}{q}+\frac{z}{r}=1

If the plane makes intercepts at (p, 0, 0), (0, q, 0) and (0, 0, r) with the axes x, y, z respectively.

Here,

p=\alpha =3a,\: q=\beta =3b,\: r=\gamma =3c

So, the equation of the plane is,

\begin{aligned} &\frac{x}{3a}+\frac{y}{3b}+\frac{z}{3c}=1\\ &\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=3 \qquad \qquad \qquad \dots(1) \end{aligned}

By comparing the equation (1) with given equation of the plane

\begin{aligned} &\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=k \end{aligned},

we get k = 3.

Posted by

Gurleen Kaur

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