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  • Need solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 26.

Need solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 26.

Answers (1)

Answer: \frac{4}{7}

Hint: \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given:

Total Possibility of cards = {1,2,3,4,5,6,7,8,9,10}

Solution:

Let       A = An even number on the card

            B = A number more than 3 on the card.

\begin{aligned} &A=\{2,4,6,8,10\} \\ &B=\{4,5,6,7,8,9,10\} \\ &A \cap B=\{4,6,8,10\} \end{aligned}
P(A) = {5}
P(B) = {7}
 

Required probability P\left(\frac{A}{B}\right)=\frac{P(A \cap B)}{P(B)}=\frac{4}{7}

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