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Need solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 9

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Answer:

 \frac{8}{65}

Hint:

\begin{aligned} &\text { Probability }=\frac{\text { No. of event favourable outcomes }}{ \text { Total no. of outcomes }} \end{aligned}

Given, events

Let A=A white or black ball in the 1st draw

       B=A white or black ball in the 2nd draw

       C=A white or black ball in the 3rd draw

Now,

\begin{aligned} &P(A)=\frac{8}{15}\\ &P\left ( \frac{B}{A} \right )=\frac{7}{14}=\frac{1}{2}\\ &P\left ( \frac{C}{B\cap A} \right )=\frac{6}{13}\\ &\text { Required Probability }=P(A\cap B\cap C)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\times P\left ( \frac{C}{B\cap A} \right )\\ &=\frac{8}{15}\times \frac{1}{2}\times \frac{6}{13}\\ &=\frac{8}{65} \end{aligned}

Posted by

Gurleen Kaur

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