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Name: Please Solve R.D.Sharma class 12 Chapter 30 Probaility Exercise 30.5 Question 3 Sub Question 1 Maths Textbook Solution.
Uploaded: Fri, 2021-09-10 15:31
Description: Please Solve R.D.Sharma class 12 Chapter 30 Probaility Exercise 30.5 Question 3 Sub Question 1 Maths Textbook Solution.

#R.D. Sharma
#Probability
#School
#Maths
#CBSE 12 Class
#RD Sharma Vol. 2 Class 12

#1.3
#10.1
#Very Short Answer type
#Multiple Choice Questions (MCQs)
#30.1
#30.2
#30.4
#30.5
#30.6
#30.7
#Case Study Based Questions (CSBQ)

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Please Solve R.D.Sharma class 12 Chapter 30 Probaility Exercise 30.5 Question 3 Sub Question 1 Maths Textbook Solution.

Answers (1)

Answer: $\frac{16}{81}$

Hint: You must know the rules of finding probability

Given: Box contains 10 black and 8 red balls

Solution: Box = (10 B and 8 R) balls

Total no. of balls = ( 10 +8) =18 balls

$P\left ( both\: red\: balls \right )$

$=\left ( \frac{8}{18}\times \frac{8}{18} \right )$

$=\frac{64}{18\times 18}$

$P=\frac{16}{81}$

Posted by

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Please Solve R.D.Sharma class 12 Chapter 30 Probaility Exercise 30.5 Question 3 Sub Question 1 Maths Textbook Solution.

Answers (1)

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