Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve RD Sharma Class 12 Chapter 23 Scalar or Dot Product Exercise Very Short Answer Question 32 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter 23 Scalar or Dot Product Exercise Very Short Answer Question 32 Maths Textbook Solution.

Answers (1)

best_answer

Answer :-   \frac{\pi}{4}

Hint :- Apply the formula of cosθ

 Given :-  |\vec{a}|=\sqrt{3} \&|\vec{b}|=2 \& \vec{a} \cdot \vec{b}=\sqrt{6}

Solution :- we know that   \cos \theta=\frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}

\begin{aligned} &\Rightarrow \cos \theta=\frac{\sqrt{6}}{\sqrt{3} * 2}\qquad[\because|\vec{a}|=\sqrt{3} \&|\vec{b}|=2 \& \vec{a} \cdot \vec{b}=\sqrt{6} \text { given }] \\ & \end{aligned}

\Rightarrow \cos \theta=\frac{\sqrt{2}}{2}

\begin{aligned} &\Rightarrow \cos \theta=\frac{1}{\sqrt{2}} \\ & \end{aligned}

\Rightarrow \theta=\frac{\pi}{4} \qquad\left[\because \cos \frac{\pi}{4}=\frac{1}{\sqrt{2}}\right]

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE announces deadline for Class 10, 12 direct admissions, subject change
anam-khan

CBSE warns about unauthorised sources offering ‘quick’ ways of getting duplicate marksheets, certificates
anam-khan

CBSE unveils 8 major changes for Class 10, 12 board exams; what students need to know

Latest Question