Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma class 12 Chapter Maxima and Minima exercise Multiple choice question, question 4 maths textbook solution.

Please solve RD Sharma class 12 Chapter Maxima and Minima exercise Multiple choice question, question 4 maths textbook solution.

Answers (1)

Answer: (d)Maximum Value < Minimum Value      

Hint: For local maxima or minima, we must havef'(x) =0.

Given: f(x)=x+\frac{1}{x}

Solution:

We have,

f(x)=x+\frac{1}{x}

f'(x)=1-\frac{1}{x^2}

For maxima and minima f'(x)=0

\Rightarrow 1-\frac{1}{x^2}=0

\Rightarrow x^2-1=0

\Rightarrow x^2=1

\Rightarrow x=\pm 1

Now,

f''(x)=\frac{2}{x^3}

f''(1)=2>0

So, x =1 is a point of local minima.

Also, f''(-1)=-2<0

So, x = -1 is a point of local maxima.

\therefore Maximum Value < Minimum Value      

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Single Girl Child Scholarship 2024: Registration extended till January 10; eligibility criteria, amount
anam-khan

CBSE wants international boards reined in; letter to education ministry seeks directions for AIU
anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14

Latest Question