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  • Please solve RD Sharma class 12 chapter Probability exercise 30.2 question 5 maths textbook solution

Please solve RD Sharma class 12 chapter Probability exercise 30.2 question 5 maths textbook solution

Answers (1)

Answer:

 \frac{11}{850}

Hint:

To find probability that each time it is card of a spade, calculate the events and take ratio with total events

Let, A =  An ace in the 1st draw

        B =  An ace in the 2nd draw

        C = Getting an ace in the 3rd draw.

Now,

\begin{aligned} &P(A)=\frac{13}{52}=\frac{1}{4}\\ &P\left ( \frac{B}{A} \right )=\frac{12}{51}=\frac{4}{17}\\ &P\left ( \frac{C}{B\cap A} \right )=\frac{11}{50}\\ &\text { Required Probability }=P(A\cap B\cap C)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\times \frac{C}{B\cap A}\\ &=\frac{1}{4}\times \frac{4}{17}\times \frac{11}{50}\\ &=\frac{11}{850} \end{aligned}

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Gurleen Kaur

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