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  • Please solve RD Sharma class 12 chapter The Plane exercise 28.4 question 5 maths textbook solution

Please solve RD Sharma class 12 chapter The Plane exercise 28.4 question 5 maths textbook solution

Answers (1)

Answer:

 \frac{-2}{7}x+\frac{3}{7}y-\frac{6}{7}z=2

Hint:

 You must know the rules of solving vector functions

Given:

 Write the normal form of the equation of the plane 2x - 3y + 6z + 14 = 0

Solution:

We have

\begin{aligned} &2x-3y+6z+14=0\\ &2x-3y+6z=-14 \end{aligned}

Now,

\begin{aligned} &\sqrt{(2)^{2}+(-3)^{2}+(6)^{2}}\\ &=\sqrt{4+9+36}\\ &=\sqrt{49}\\ &=7 \end{aligned}

So, divide the given equation by 7

We get,

\begin{aligned} &\frac{2}{7}x-\frac{3}{7}y+\frac{6}{7}z=\frac{-14}{7}\\ &\frac{2}{7}x-\frac{3}{7}y+\frac{6}{7}z=-2 \end{aligned}

Balance the -ve sign,

\begin{aligned} &\frac{-2}{7}x+\frac{3}{7}y-\frac{6}{7}z=2 \end{aligned}

This is the normal form of the given equation of the plane.

Posted by

Gurleen Kaur

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