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Provide Solution For  R.D. Sharma Maths Class 12 Chapter 28 The Plane Exercise 28.13 Question 9 Sub Question 2 Maths Textbook Solution.

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\begin{aligned} &\left(\begin{array}{ccc} x & y & z \\ -3 & -4 & 2 \\ 2 & 1 & 5 \end{array}\right)=\mathrm{d} \\ &(-20-2) 2-y(-15-4)+2(-3+8)=d-22 z+19 y+5 z=d \end{aligned}

The line  \frac{x-1}{-3}=\frac{y-2}{-2k}=\frac{z-3}{2} pass through the point (1,2,3) so putting x=1,y=2,z=3  is the equation we get

Therefore the equation of the plane containing the lines is -22x+19y+5z=31

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