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Provide solution for RD Sharma maths class 12 chapter 22 Algebra of vectors exercise 22.8 question 5 sub question 2 maths textbook solution

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Answer: vectors are co-planar

Hint: If vectors are given express as linear combination

\RightarrowGiven vectors as follows:

Let,

\begin{aligned} &P=\hat{i}+\hat{j}+\hat{k} \\ &Q=2 \hat{i}+3 \hat{j}-\hat{k} \\ &R=-\hat{i}-2 \hat{j}+2 \hat{k} \\ &P=x Q+y R \\ &\hat{i}+\hat{j}+\hat{k}=x(2 \hat{i}+3 \hat{j}-\hat{k})+y(-\hat{i}-2 \hat{j}+2 \hat{k}) \\ &\hat{i}+\hat{j}+\hat{k}=\hat{i}(2 x-y)+\hat{j}(3 x-2 y)+\hat{k}(-x+2 y) \end{aligned}

Comparing coefficient of \hat{i},\hat{j} & \hat{k}  on both sides

2x-y=1                                            ........(1)

3x-2y=1                                         .........(2)

-x+2y=1                                        ..........(3)

Add eqn (2) and (3)

3x-2y=1

\underline{-x+2y=1}

2x              =2

x=1

Put, x = 1 in (3)

\begin{aligned} &-1+2 y=1 \\ &2 y=1+1 \\ &y=\frac{2}{2}=1 \\ &\text { Put, } x=1 \& y=1 in\left ( 1 \right ) \end{aligned}

L.H.S=2x-y

=2\left ( 1 \right )-\left ( 1 \right )

=2-1

=1

=R.H.S

As values satisfies the third equation we can say that the given vectors are coplanar

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