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  • Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.1 question 2

Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.1 question 2

Answers (1)

Answer:

 \frac{1}{2}, \frac{1}{3}

Hint:

Use Formula

\text { Probability }=\frac{\text { No. of event happened }}{ \text { Total no. of events }}

As per question,

Let , S = Elements of all certain possibilities

            =  { (B1B2), (B1G2), (G1G2), (G1B2) }

Now,  A  = Event where both child is girl

                =  { (G1 , G2) }

  B = Event where youngest child is a girl

     =  { (B1G2), (G1G2) }

 C = At Least one child is a girl

    = { (B1G2), (G1G2), (G1B2) }

Now,

  A ∩ B = (G1G2)

  A ∩ C = (G1G2) 

  1. Now,

Required probability

                    \begin{aligned} &=\frac{n(A \cap B)}{n(B)}\\ &=\frac{1}{2} \end{aligned}

2. Required probability

                \begin{aligned} &=\frac{n(A \cap B)}{n(C)}\\ &=\frac{1}{3} \end{aligned}

Posted by

Gurleen Kaur

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