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Provide solution for RD Sharma maths class 12 chapter Probability exercise 30.2 question 6 subquestion (i)

Answers (1)

Answer:

 \frac{1}{221}

Hint:

 \begin{aligned} &\text { Probability }=\frac{\text { No. of event favourable outcomes }}{ \text { Total no. of outcomes }} \end{aligned}

Given events

            Let A=A king in 1st draw

                  B= A king in 2nd draw

Solution:

\begin{aligned} &P(A)=\frac{4}{52}=\frac{1}{13}\\ &P\left ( \frac{B}{A} \right )=\frac{3}{51}=\frac{1}{17}\\ &\text{ Required Probability }=P(A\cap B)\\ &=P(A)\times P\left ( \frac{B}{A} \right )\\ &=\frac{1}{13}\times \frac{1}{17}\\ &=\frac{1}{221} \end{aligned}

Posted by

Gurleen Kaur

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