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  • Provide solution RD Sharma maths class 12 chapter 12 Derivative as a Rate Measure exercise case study based question, question 1 sub question 5 maths textbook solution

Provide solution RD Sharma maths class 12 chapter 12 Derivative as a Rate Measure exercise case study based question, question 1 sub question 5 maths textbook solution

Answers (1)

Answer:

-\frac{31}{18}

Hint:

  Here, we use basic concepts of area

Given:

 x=8 y=6

Solution:

 x=8 y=6

So, according to Pythagoras

P=10

So, change of ratio of length and breadth =\frac{d}{d t}\left(\frac{x}{y}\right)=\frac{\frac{y d x}{d t}-x \frac{d y}{d t}}{y^{2}}

                                          =-31 / 36 \quad, \text { since } \frac{d x}{d t}=-5 \text { and } \frac{d y}{d t}=4

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