The resistance of a Conductor-
The property of a conductor due to which it opposes the flow of current through it is called resistance.
From Ohm's law, we can say that
The resistance of a conductor is numerically equal to the ratio of potential difference across its ends to the current flowing through it.
$$
\text { Resistance }=\frac{\text { Potential difference }}{\text { Current }} \text { or } \quad R=\frac{V}{I}
$$
The SI unit of resistance is ohm which is denoted by the symbol omega, $(\Omega)$
Now, if the potential difference V is 1 volt and the current $I$ is 1 ampere, then resistance $R$ in the above equation becomes 1 ohm.
That is,
$$
1 \mathrm{ohm}=\frac{1 \text { volt }}{1 \text { ampere }}
$$
Resistance of the conductor depends on
the length of the conductor. I.e A long wire (or conductor) has more resistance and a short wire has less resistance.
The thickness of the conductor. I.e a thick wire has less resistance whereas a thin wire has more resistance.
nature of the material of the conductor.
the temperature of the conductor. I.e Rise in temperature of a wire (or conductor) increases its resistance.
From this dependency, we can say that
The resistance of a uniform metallic conductor is directly proportional to its length (L) and inversely proportional to the area of cross-section (A)
I.e
$$
\begin{aligned}
& \quad R \propto \text { land } \quad R \propto \frac{1}{A} \\
& \text { we get } \\
& R \propto \frac{l}{A} \\
& \text { or. } R=\rho \frac{l}{A}
\end{aligned}
$$
where $\rho$ (rho) is a constant of proportionality and is called the electrical resistivity of the material of the conductor.
The SI unit of resistivity is $\Omega \mathrm{m}$. It is a characteristic property of the material.
Both the resistance and resistivity of a material vary with temperature.
Fact-
The metals and alloys have very low resistivity in the range of $10^{-8} \Omega \mathrm{~m}$ to $10^{-6} \Omega \mathrm{~m}$ . They are good conductors of electricity. Insulators like rubber and glass have a resistivity of the order of $10^{12} \Omega \mathrm{~m}$ to $10^{17} \Omega \mathrm{~m}$.
- Formula-
For a conductor of resistivity $\rho$ having a length of a conductor= I
and Area of a crosssection of conductor= A
Then the resistance of a conductor is given as
$$
R=\rho \frac{l}{A}
$$
Where $\rho \rightarrow$ Resistivity
Exam | Chapter |
JEE FOUNDATION | Electricity |
The potential difference between two points of a wire carrying a 4-ampere current is 0.2 volt. Calculate the resistance between these points.
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An electric iron draws a current of 2 A from the 110 V supply line. What current will this electric iron draw when connected to the 220 V supply line?
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A copper wire of length 3 m and area of cross-section 1.7 × 10–6 m2 has a resistance of 3 × 10–2 ohms. Calculate the resistivity of copper.
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Resistance to the flow of current is due to
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Among which of the following quantity, resistance does not depend upon
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The resistance of a wire is 'R' ohm. If it is melted and stretched to 'n' times its original length, its new resistance will be :
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A metal wire having resistance R, stretched in such a way that its radius becomes half. The new value of resistance is
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When the area of cross-section of a conductor is doubled, its resistance becomes :
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A material B has twice the specific resistance of A. The cross-section wire B has twice the diameter of a wire A. Then for the two wires to have the same resistance, the ratio of their respective lengths must be
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The length of a given cylindrical wire is increased by 100%. Due to the consequent decrease in diameter, the change in the resistance of the wire will be (in %)
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