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KVL - (Concept)
Kirchoff's second law
The algebraic sum of all the potential across a closed loop is zero. This law is also known as Kirchhoff's Voltage law (KVL)
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Change in Potential in traversing a resistance is -iR
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Change in Potential in the opposite direction is iR
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Traversing an e.m.f source from negative to positive terminal is -E
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While in the opposite direction is E
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Change in Potential in traversing a capacitor from negative to positive $\frac{q}{C}$
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While in the opposite direction is -$\frac{q}{C}$
In closed-loop
$-i_1 R_1+i_2 R_2-E_1-i_3 R_3+E_2+E_3-i_4 R_4=0$
| Exam | Chapter |
| JEE FOUNDATION | Electricity |
The Kirchhoff’s first law $\left(\sum i=0\right)$ and second law $\left(\sum i R=\sum E\right)$ where the symbols have their usual meanings, are respectively based on
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In the given circuit which of the following equations is correct?
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In the circuit shown, the current in the 1 resistor is :
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In the electric network shown, when no current flows through the $4 \Omega$ resistor in the arm EB, the potential difference (in V ) between the points A and D will be :
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A 10 V battery with internal resistance and a 15 V battery with internal resistance are connected in parallel to a voltmeter (see figure). The reading (in V) in the voltmeter will be close to :
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A battery connected with two resistors in series is shown below. If the voltage of one resistor is 9 V, what is the voltage across the other resistor?
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Find the equivalent resistance between the point a and b of the circuit shown in figure.
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Consider the circuit shown below where all resistors are of $1 k \Omega$ If a current of magnitude $1 m A$ flows through a resistor marked X, what is the potential difference measured between points $P$ and $Q$?
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