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  • 500g of water and 100g of ice at  are in a calorimeter whose water equivalent is 40g. 10g o

500g of water and 100g of ice at 0^{\circ}C are in a calorimeter whose water equivalent is 40g. 10g of steam at 100^{\circ}C is added to it. Then water in the calorimeter is (Latent heat of ice=80 cal/g , Latent heat of steam=540 cal/g) 

Option: 1

580g


Option: 2

590g


Option: 3

600g


Option: 4

610g


Answers (1)

best_answer

Here, the energy released by the condensation of vapour is not sufficient to melt the whole ice. So, the amount of energy released by the water vapour, when it condensed and comes to 00C is,

\begin{array}{l} E=m_{\text {vapour}} L_{\text {vapour }}+m_{\text {vapour}} S_{\text {water}} \times 100 \\ \Rightarrow E=10 \times 540+10 \times 1 \times 100 \\ \Rightarrow E=6400 \mathrm{cal} \end{array}

So, let m' mass of the ice is melted

 Therefore,

m^{\prime} L_{i c e}=6400 \Rightarrow m^{\prime}=\frac{6400}{80} \Rightarrow m^{\prime}=80 g m

Therefore, the total amount of water in the capillary tube is,

m_{0}=500+80+10 \Rightarrow m_{0}=590 g m

 

Posted by

Ajit Kumar Dubey

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