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  • 5.325 g sample of Methyl Benzoate, a compound used in the manufacturing of perfumes, is found to contain 3.758 g of Carbon, 0.316 g of Hydrogen and 1.251 g of Oxygen. What is the empirical formula of the compound?

5.325 g sample of Methyl Benzoate, a compound used in the manufacturing of perfumes, is found to contain 3.758 g of Carbon, 0.316 g of Hydrogen and 1.251 g of Oxygen. What is the empirical formula of the compound?

Answers (1)

best_answer

percent composition of each elements,

for C  = 3.758/5.325 \approx70%

for H = 0.316/5.325 \approx 5%

for O = 1.251/5.325 \approx23%

Molecular wt of methylbenzoate = 136g/mol

So,moles of each element in one mole of compound = 

for C = (70/100)/136 \approx 95.9g

for H = (5/100)/136 \approx 8g

for O =(23/100)/136\approx 31.9g

Moles of individual element 

C 95.9/24 \approx 8

H = 8/1 = 8

O =31.9/16 \approx 2

Divide by smallest no. of moles we get C:H:O = 4:4:1
So the empirical formula  is C_{4}H_{4}O

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manish

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