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A current I flow in an infinetly long wire cross - section in form of a semicircular ring of radius R. The magnitude of the magnetic field i

how the answer will be ?

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 dI = \frac{d\Theta }{\pi}I

dB=\frac{\mu o}{4\pi}\cdot \frac{2I}{R}=\frac{\mu oI}{2\pi^{2}R}d\Theta \rightarrow M.Fat centre due to this portion

Net magnetic field

B=\int_{-\frac{\pi }{2}}^{+\frac{\pi }{2}}dBcos\Theta \rightarrow  

B=\int_{-\frac{\pi }{2}}^{+\frac{\pi }{2}}\frac{\mu oI}{2\pi^{2}R}cos\Theta d\Theta = \frac{\mu oI}{\pi^{2}R}

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