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  • Answer please! - Sets, Relations and Functions - JEE Main-5

Let P=\left \{ (x,y)|x^{2}+y^{2}=1,x,y\epsilon R \right \}. Then P is

  • Option 1)

    Reflexive

  • Option 2)

    Symmetric

  • Option 3)

    Transitive

  • Option 4)

    Anti-symmetric

 

Answers (1)

best_answer

As we learnt

 

TRANSITIVE RELATION -

 

A relation R in A is said to be transitive, if a R b and b R c ⇒ a R c ∀ a,b,c ∈ A

-

 

 The relation is not reflexive and symmetric but it is symmetric; because x^{2}+y^{2}= 1\Rightarrow y^{2}+x^{2}= 1

 


Option 1)

Reflexive

Option 2)

Symmetric

Option 3)

Transitive

Option 4)

Anti-symmetric

Posted by

Himanshu

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