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  • Can someone explain - For the following reaction , the mass of water produced from 445 g of is : - Some basic concepts in chemistry - JEE Main

For the following reaction , the mass of water produced from 445 g of C_{57}H_{110}O_{6}   is :

2C_{57}H_{110}O_{6}(s)+ 163O_{2}(g)\rightarrow 114CO_{2}(g)+110H_{2}O(1)

  • Option 1)

    495g

  • Option 2)

    890 g

  • Option 3)

    445 g

  • Option 4)

    490 g

Answers (1)

best_answer

 

Molar Mass -

The mass of one mole of a substance in grams is called its molar mass.

- wherein

 Molar mass of water = 18 g mol-1

Mole Fraction -

It is ratio of moles of solute or moles of solvent to moles of solution.

- wherein

If a substance ‘A’ dissolves in substance ‘B’ and their number of moles are n_{A} and n_{B} respectively; then the mole fractions of A and B are given as

Mole fraction of A = (number of moles of A)/(number of moles of solution ) = n_{A}/(n_{A}+ n_{B})

Molecular Formula -

The molecular formula shows the exact number of different types of atoms present in a molecule of a compound.

- wherein

For glucose, empirical formula is CH2O .its molar mass is 180 gram.

n = molar mass/empirical formula mass = 180/30=6

Hence molecular formula= C6H12O6

The mole of C_{57}H_{110}O_{6}(s)=\frac{445}{890}=0.5 moles 

2C_{57}H_{110}O_{6}(s)+163 \; O_{2}(g)\rightarrow 114 CO_{2}(g)+110 \; H_{2}O(l)

nH_{2}O=\frac{110}{4}=\frac{55}{2}

mH_{2}O=\frac{55}{2}\times 18=495 gm

 


Option 1)

495g

Option 2)

890 g

Option 3)

445 g

Option 4)

490 g

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