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In a Wheatstone bridge (see fig.) , resistances P and Qare approximately equal. When R = 400\Omega, the bridge is balanced. On interchanging P and , the valueof R, for balance, is 405\Omega. The value of X is close to:

  • Option 1)

    401.5 ohm

  • Option 2)

     

    404.5 ohm

  • Option 3)

     

    403.5 ohm

  • Option 4)

     

    402.5 ohm

Answers (1)

best_answer

 

Balanced Bridge -

\frac{P}{Q}= \frac{R}{S}

- wherein

V_{B} = V_{D}

( Balanced condition )

No current will flow through galvanometer

400=x\frac{P}{Q}

405=x\frac{Q}{P}

x^{2}=400\times 405

x=\sqrt{400\times 405}

=20\sqrt{405}

402.5\Omega

 

 


Option 1)

401.5 ohm

Option 2)

 

404.5 ohm

Option 3)

 

403.5 ohm

Option 4)

 

402.5 ohm

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