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  • Can someone explain The equivalent conductances of sodium, Chroride, hydrochlroic acid and sodium acetate at infinite dilution are 126.45, 426.16 and 91 ohm-1cm2eq-1,respectively at 25oC. Calculate the equivalent conductance of acetic acid at infinit

The equivalent conductances of sodium, Chroride, hydrochlroic acid and sodium acetate at infinite dilution are 126.45, 426.16 and 91 ohm-1cm2eq-1, respectively at 25oC. Calculate the equivalent conductance of acetic acid at infinite dilution.

  • Option 1)

    370.8 ohm-1cm2eq-1

  • Option 2)

    390.7 ohm-1cm2eq-1

  • Option 3)

    377.7 ohm-1cm2eq-1

  • Option 4)

    407.7 ohm-1cm2eq-1

 

Answers (1)

As we have learnt,

 

Formula for limiting molar conductivity for electrolyte -

\Lambda_{m}^{0}= \lambda _{+}^{0}.\nu _{+}\:+\:\nu _{-}.\lambda_{-}^{0}

\lambda _{+}^{0}\:and\:\lambda_{-}^{0}

are limiting molar conductivities of cation and anion respectively.

- wherein

if an electrolyte on dissociation gives \nu_{+} \:cation\:and\: \nu_{-} anions.

 

 \\*\Lambda_{\infty\;CH_3COONa} = \lambda_{CH_3COO^-} + \lambda_{Na^+} = 91 \;\;\; -(1) \\*\Lambda_{\infty\;HCl} = \lambda_{H^+} + \lambda_{Cl^-} = 426.16\;\;\;- (2) \\*\Lambda_{\infty\;NaCl} = \lambda_{Na^+} + \lambda_{Cl^-} = 126.45\;\;\; -(3)

Addding 1& 2 and subtracting 3, we get 

\Lambda_{\infty\;CH_3COOH} = \lambda_{CH_3COO^-} + \lambda_{H^+} = 390.7 ohm^{-1}cm^2{eq^{-1}}

 


Option 1)

370.8 ohm-1cm2eq-1

Option 2)

390.7 ohm-1cm2eq-1

Option 3)

377.7 ohm-1cm2eq-1

Option 4)

407.7 ohm-1cm2eq-1

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subam

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