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  • Can someone explain What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?

What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?

  • Option 1)

    Cr^{3+} and Cr_2O_7\: ^{2-} are formed

  • Option 2)

    Cr_2O_7\: ^{2-} and H_2O are formed

  • Option 3)

    CrO_4\: ^{2-} is reduced to +3 state of  Cr

  • Option 4)

    CrO_4\: ^{2-} is oxidised to +7 state of  Cr

 

Answers (1)

best_answer

As we learned

 

Oxides of 3d metals -

The ability of oxygen to stabilise the highest oxidation number in the oxides of 'd' block elements are shown in the table or shown in fig.

 

-

 

 Reaction between Potassium Chromate and dilute HNO3 gives,

2KCrO_{4}+2HNO_{3}\rightarrow K_{2}Cr_{2}O_{7}+2KNO_{3}+H_{2}O

Here, Cr_{2}O_{7}^{2-} and H_{2}O are formed

 


Option 1)

Cr^{3+} and Cr_2O_7\: ^{2-} are formed

Option 2)

Cr_2O_7\: ^{2-} and H_2O are formed

Option 3)

CrO_4\: ^{2-} is reduced to +3 state of  Cr

Option 4)

CrO_4\: ^{2-} is oxidised to +7 state of  Cr

Posted by

prateek

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