A particle of mass ‘m’ and charge ‘q’ is accelerated through a potential difference of V volt, its energy will be
qV
mqV
As we have learnt,
Electron Volt -
It is the smallest practical unit of energy if used in atomic and nuclear Physics.
- wherein
.
KE = qV
Option 1)
qV
Option 2)
mqV
Option 3)
Option 4)
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