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Electric potential at an equatorial point of a small dipole with dipole moment p (r, distance from the dipole) is

  • Option 1)

    zero 

  • Option 2)

    \frac{p}{4\pi \varepsilon _0 r^2}

  • Option 3)

    \frac{p}{4\pi \varepsilon _0 r^3}

  • Option 4)

    \frac{2p}{4\pi \varepsilon _0 r^3}

 

Answers (1)

best_answer

As we have learned

if r>>l -

E_{axi}=\frac{1}{4\pi \epsilon _{0}}\frac{2P}{r^{3}}

V_{axi}=\frac{1}{4\pi \epsilon _{0}}\frac{P}{r^{2}}

- wherein

Angle between Eaxi and P is 0.

 

  because at perpendicular bisector potential due to equal and opposite charges is zero .

 


Option 1)

zero 

Option 2)

\frac{p}{4\pi \varepsilon _0 r^2}

Option 3)

\frac{p}{4\pi \varepsilon _0 r^3}

Option 4)

\frac{2p}{4\pi \varepsilon _0 r^3}

Posted by

prateek

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