Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Confused! kindly explain, - The actual value of resistance R, shown in the figure is 30 . This is measured in an experiment as - Current Electricity - JEE Main

The actual value of resistance R, shown in the figure is 30 \Omega . This is measured in an experiment as shown using the standard formula R= \frac{V}{I}, Where V\: and\: I are the reading of the voltmeter and ammeter, respectively. If the measured value of R is 5% less, then the internal resistance of the voltmeter is:

  • Option 1)

    570\: \Omega

  • Option 2)

    35 \: \Omega

  • Option 3)

    350\: \Omega

  • Option 4)

    600\: \Omega

Answers (1)

best_answer

 

Conversion of galvanometer into ammeter -

Connect a low resistance in parallel to the galvanometer

- wherein

 

 

Conversion of galvanometer into voltameter -

Connected a large Resistance R  in series

- wherein

0.95 R = \frac{RR_{v}}{R+R_{v}}

0.95 \times 30 = 0.05R_{v}

R_{v} = 570.2

 


Option 1)

570\: \Omega

Option 2)

35 \: \Omega

Option 3)

350\: \Omega

Option 4)

600\: \Omega

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’
anam-khan

NIT Puducherry Cut-off 2024: Computer Science and Engineering had highest closing rank last year
anam-khan

What after JEE Main results 2024? All you need to know about JEE Adv, CSAB, JoSAA counselling

Latest Question