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Options are ....

I) 20,30

ii) 30,40

iii)40,30

iv) 30,20

Answers (1)

best_answer

molar mass of B2A3 = 9/0.05 = 2B + 3A =180

molar mass of B2A = 10/0.1 = 2B+ A = 100

here A = 100 - 2B
 subustitute the value of A in 1st eq., we get , 2B +3 (100-2B) = 180

                                                                          2B +300 -6B = 180 

                                                                          here w get B =30
                                                              put the value of B in eq 2nd we get A = 40 
 

hence, option (iii)

is correct                                                              

Posted by

manish

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