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A ball of mass 1 g and charge 10-8 moves from a point A. where potential is 600 volt to the point B where potential is zero. Velocity of the ball at the point B is 20 cm/s. The velocity of the ball at the point A will be

  • Option 1)

    22.8 cm/s

  • Option 2)

    228 cm/s

  • Option 3)

    16.8 m/s

  • Option 4)

    168 m/s

 

Answers (1)

As we have learnt,

 

Work energy relation -

W= U_{f}-U_{i}

 

 

- wherein

U_{f}- \, final\, P.E

U_{i}-\, initial\, P.E.

 

 By using,

\frac{1}{2}m(v_1^{2}- v_2^{2}) \Rightarrow \frac{1}{2}\times 10^{-3}(v_{1}^{2} - (0.2)^{2}) = 10^{-8}(600 - 0)\Rightarrow v_1 = 22.8cm/s

 


Option 1)

22.8 cm/s

Option 2)

228 cm/s

Option 3)

16.8 m/s

Option 4)

168 m/s

Posted by

Vakul

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