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  • I have a doubt, kindly clarify. - Electrostatics - JEE Main-2

With the rise in temperature, the  dielectric constant K of a liquid

  • Option 1)

    Increases             

  • Option 2)

     Decreases

            

  • Option 3)

     Remains unchanged  

  • Option 4)

    Charges erratically

 

Answers (1)

best_answer

As we learned

When dielectric insert between the charges -

F_{med}=\frac{F_{air}}{K}=\frac{1q_{1}q_{2}}{4\pi \varepsilon _{0}kr^{2}}

- wherein

 

 With temperature rise, dielectric constant of liquid decreases

 


Option 1)

Increases             

Option 2)

 Decreases

        

Option 3)

 Remains unchanged  

Option 4)

Charges erratically

Posted by

Plabita

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