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  • I need help with - A mixture of 2 moles of helium gas (atomic mass =4 u), and 1 mole of argon gas (atomic mass = 40 u) - Kinetic theory of Gases - JEE Main

A mixture of 2 moles of helium gas (atomic mass =4 u), and 1 mole of argon gas (atomic mass = 40 u) is kept at 300 K in a container. The ratio of their rms speeds \left [ \frac{V_{rms}(helium)}{V_{rms}(argon)} \right ], is close to:

  • Option 1)

    3.16

  • Option 2)

    0.32

  • Option 3)

    0.45

  • Option 4)

    2.24

Answers (1)

best_answer

 

Root mean square velocity -

V_{rms}= \sqrt{\frac{3RT}{M}}

= \sqrt{\frac{3P}{\rho }}
 

- wherein

R = Universal gas constant

M = molar mass

P = pressure due to gas

\rho = density

 

V_{rms} = \sqrt{\frac{3RT}{M}}

\frac{V_{rms} (He)}{V_{rms}(Ar)} = \sqrt{\frac{M_{Ar}}{M_{He}}} = \sqrt{\frac{40}{4}} \ = \sqrt{10}

= 3.16


Option 1)

3.16

Option 2)

0.32

Option 3)

0.45

Option 4)

2.24

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