If A is a square matrix of order n and k is a scalar, then, adj(kA) is equal to
adj(A) if n=1
adj(A) if k=1
kn-1Iadj(A)I
Both a and b is correct
Properties of adjoint of Matrix - Part 2 -
Properties of adjoint of matrix
6. If A is a square matrix of order n and k is a scalar, then, adj(kA) = kn- 1·(adj A)
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Using property adj(kA) = kn-1·(adj A)
put n=1
adj(kA) = k1-1·(adj A)=adj A
pur k=1
adj(A) = 1n-1·(adj A)=adj A
hence,
both a and b is correct
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