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All the metal ions contains t_{2g}^{6} e_{g}^{0} configurations. Which of the following complex will be paramagnetic?

  • Option 1)

    [FeCl(CN)_4(O_2)]^{4-}

  • Option 2)

    K_4[Fe(CN)_6]

  • Option 3)

    [Co(NH_3)_6]Cl_3

  • Option 4)

    [Fe(CN)_5(O_2)]^{-5}

 

Answers (1)

As we have learned

Delta o and P (Pairing energy) -

\Delta \circ < P No pairing, weak field ligand

\Delta \circ > P Pairing, strong field ligand 

-

 

 (A)        [FeCl(CN)4(O2)]4–  ; O2 is O22– ; CN is strong field ligand, so compels for the pairing of electrons.  

Fe^3+\rightarrow 3d^5

B)         K4[Fe(CN)6]                    ;  CN is strong field ligand so compels for the pairing of electrons.

Fe^2+\rightarrow 3d^6

(C)        [Co(NH3)6]Cl3  ; NH3 is strong field ligand and 3d6 configuration has higher CFSE compelling for the pairing of electrons.

CO^3+\rightarrow 3d^6

(D)        [Fe(CN)5(O2)]5–   ; O2 is O22– ; CN is strong field ligand so compels for the pairing of electrons.

Fe^2+\rightarrow 3d^6

 

 

 


Option 1)

[FeCl(CN)_4(O_2)]^{4-}

Option 2)

K_4[Fe(CN)_6]

Option 3)

[Co(NH_3)_6]Cl_3

Option 4)

[Fe(CN)_5(O_2)]^{-5}

Posted by

Vakul

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