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the number of atoms in 558.5 gram Fe(at wt. of Fe = 55.85 g/mol) is?

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Given 

amount of Fe = 558.5 g

Molecular weight of Fe = 55.85 g/mol

So,

The number of moles of Fe :

=\frac{given\:mass}{molecular\:mass}=\frac{558.5}{55.85}=10\:mol

Now as we know 

Number of atoms in one mol = 6.022\times10^{23}

So,

Number of atoms in 10 mols = 10\times6.022\times10^{23}

                                              = 6.022\times10^{24}

Hence there are 6.022\times10^{24} atoms in 558.5 g of Fe.

Posted by

Pankaj Sanodiya

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