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  • Please help! Excited hydrogen atom emits light in the ultraviolet region at 2.47 x 1015 Hz. With this frequency, the energy of a single photon is :(h = 6.63 x 10-34 Js)

 Excited hydrogen atom emits light in the ultraviolet region at 2.47 x 1015 Hz. With this frequency, the energy of a single photon is :

(h = 6.63 x 10-34 Js)

  • Option 1)

    8.041 x 10-40 J

  • Option 2)

    2.680 x 10-19 J

  • Option 3)

    1.640 x 10-18 J

  • Option 4)

    6.111 x 10-17 J

 

Answers (2)

best_answer

As discussed in the concept

The energy (E) of a quantum of radiation -

E=hv

Where h is plank’s constant and \nu is frequency

-

 

 E = 6.62\times10^{-34}\times2.47\times10^{15}

E = 1.64\times10^{-18}J

Option 3 is the correct option

 


Option 1)

8.041 x 10-40 J

Incorrect option

Option 2)

2.680 x 10-19 J

Incorrect Option

Option 3)

1.640 x 10-18 J

Correct Option

Option 4)

6.111 x 10-17 J

Incorrect option

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solutionqc

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