Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

If E  is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional  to  

  • Option 1)

    E\;

  • Option 2)

    \; E^{2}\;

  • Option 3)

    \; \frac{1}{E^{2}}\;

  • Option 4)

    \; E^{3}

 

Answers (1)

best_answer

As we learned

Electric Field -

The space around a charge in which another charged particle experiences a force is said to have electric field in it.

- wherein

 

 Electrostatic energy density \frac{dU}{dV}=\frac{1}{2}K\varepsilon _{0}E^{2}

 


Option 1)

E\;

Option 2)

\; E^{2}\;

Option 3)

\; \frac{1}{E^{2}}\;

Option 4)

\; E^{3}

Posted by

prateek

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024: NTA debars 39 candidates for 3 years on account of using unfair means
anam-khan

JEE Main 2024 session 2 paper 2 answer key objection window closes today; fees
anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’

Latest Question