For two 3 × 3 matrices A and B, let A + B = 2B' and 3A + 2B = I3, where B' is the transpose of B and I3 is 3 × 3 identity matrix. Then :
5A + 10B = 2I3
10A + 5B = 3I3
B + 2A = I3
3A + 6B = 2I3
As we have learned
Property of Transpose -
- wherein
and being conformable matrices and is transpose of
We have
A + B = 2B' .............(1)
A' + B' = 2B ...........(2)
Also 3A +2B =
3A' + 2B' = ....(3)
from 1 and 3
from 2 and 3
from 4 and 5
now we have ,
3A+2B =
11B -A = 2
On solving ,
35B = 7
B = /5
and
A = /5
Option 1)
5A + 10B = 2I3
Option 2)
10A + 5B = 3I3
Option 3)
B + 2A = I3
Option 4)
3A + 6B = 2I3
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