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A 500 \muF capacitor is charged at a steady rate of 100 \muC/sec. The potential difference across the capacitor will be 10 V after an interval of 

  • Option 1)

    5 sec

  • Option 2)

    20 sec

  • Option 3)

    25 sec

  • Option 4)

    50 sec

 

Answers (1)

best_answer

As we have learnt,

 

Time Constant -

The Quantity RC is called the time constant.

At t=\tau =RC

Q=Q_{0}\left ( 1-\frac{1}{e} \right )=0.63Q_{0}   

=63% of Q0.

-

 

 Charge required to reach the capacitor upto 10 V is

Q = 500\times 10^{-6}\times 10=5\times 10^{-3}

Now required time=\frac{5\times 10^{-3}}{100\times 10^{-6}} = 50 sec

 


Option 1)

5 sec

Option 2)

20 sec

Option 3)

25 sec

Option 4)

50 sec

Posted by

Avinash

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