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  • Stuck here, help me understand: An air bubble of radius 0.1 cm is in a liquid having surface tension 0.06 N/m and density 103 kg/m3. The pressure inside the bubble is 1100 Nm-2 greater than the atmospheric pressure. At what depth is the bubble below

An air bubble of radius 0.1 cm is in a liquid  having surface tension 0.06 N/m and density 103 kg/m3.  The pressure inside the bubble is 1100 Nm-2 greater than the atmospheric pressure.  At what depth is the bubble below the surface of the liquid ? (g = 9.8 ms-2)

  • Option 1)

    0.1 m

  • Option 2)

    0.15 m

  • Option 3)

    0.20 m

  • Option 4)

    0.25 m

 

Answers (1)

best_answer

As we have learned

Excess pressure for concave surface -

\Delta P= \frac{2T}{R}

-

 

 Radius of air bubble = 0.1 cm 

 surface tension S = 0.06 N/m 

\rho = 10 ^3 Kg /m^2\\\Delta p = 1100 N/ m ^2 = \Delta p = \rho gh + \frac{2S }{r }

\Rightarrow 1100 = 9.8 \times 10^3 \times h + \frac{2 \times 6\times 10^{-2}}{10^{-3}}\\1100 = 9800 h + 120 \\h = {980}/{9800}= 0.1 m

 

 

 

 

 


Option 1)

0.1 m

Option 2)

0.15 m

Option 3)

0.20 m

Option 4)

0.25 m

Posted by

SudhirSol

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